Hi,
Tim Rhodes <proftim@speakeasy.org> writes:
<<
Eric Boyd wrote:
>consider a 3 digit number
>
>abc
>
>it "reverse" is
>
>cba
>
>the difference between them is
>
>absolute value (cba-abc)
Should that be |(c*100+b*10+a)-(a*100+b*10+c)| ?
>>
If you want to define it that way. I admit I was lax in my notation, but at least I was consistent. I was letting the letter stand for the digits, and not the actual value those digits yield when combined into a number.
For those who read my post in detail, there is an error having to do with a "carry the one"; the second digit is 9, not zero as I wrote. Note also that there are many cases (when a=c) where the final result is simply zero.
ERiC